mysql查询当天所有数据sql语句
mysql查询当天的所有信息：
| 代码如下 | |
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select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now()) |
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这个有一些繁琐，还有简单的写法：
| 代码如下 | |
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select * from table where date(regdate) = curdate(); |
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另一种写法没测试过
查询当天的记录
| 代码如下 | |
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select * from hb_article_view where TO_DAYS(hb_AddTime) = TO_DAYS(NOW()) |
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date()函数获取日期部分, 扔掉时间部分，然后与当前日期比较即可
补充：本周、上周、本月、上个月份的数据
查询当前这周的数据
| 代码如下 | |
| SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now()); | |
查询上周的数据
| 代码如下 | |
| SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1; | |
查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查询距离当前现在6个月的数据
| 代码如下 | |
| select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now(); | |
查询上个月的数据
| 代码如下 | |
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select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from `user` where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * select * |
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select *
from [user]
where pudate between 上月最后一天
and 下月第一天
mysql查询多少秒内的数据
| 代码如下 | |
| SELECT count( * ) AS c, sum( if( logusertype =2, logusertype, 0 ) ) /2 AS a, sum( if( logusertype =3, logusertype, 0 ) ) /3 AS b FROM testlog WHERE UNIX_TIMESTAMP(NOW())-UNIX_TIMESTAMP( logendtime )<=30 |
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查询30秒内记录的总数，loguser等于2的记录的总数和，和 loguser等于3的记录的总数.
if( logusertype =2, logusertype, 0 ) 如果logusetype等于2 就在logusertype上累加，否则加0。
sum( if( logusertype =2, logusertype, 0 ) ) 把logusertype都累加起来。
sum( if( logusertype =2, logusertype, 0 ) ) /2 AS a, 除以2是统计个数。
UNIX_TIMESTAMP(NOW())计算当前时间的秒数，
UNIX_TIMESTAMP( logendtime )计算logendtime的秒数
